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  Вопрос: MD5 - алгоритм шифрования. Добавлено: 23.07.05 15:07  

Автор вопроса:  MixeR
В какую сторону капать...чтобы можно было зашифровать и расшифровать строку по алгоритму MD5. Актуально как для VB6 так и для VB.NET.

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  Ответы Всего ответов: 23  

Номер ответа: 1
Автор ответа:
 GSerg



Вопросов: 0
Ответов: 1876


 Профиль | | #1 Добавлено: 23.07.05 15:09
MD5 не есть алгоритм шифрования...

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Автор ответа:
 MixeR



Вопросов: 12
Ответов: 25
 Профиль | | #2 Добавлено: 23.07.05 15:39
А что же это по-вашему?

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Автор ответа:
 HACKER


 

Разработчик Offline Client

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 Профиль | | #3 Добавлено: 23.07.05 15:42
ага, MD5 это заливная рыба :) ...

Класс:


Option Explicit

'/******************************************************************************
' *  Copyright (C) 2000 by Robert Hubley.                                      *
' *  All rights reserved.                                                      *
' *                                                                            *
' *  This software is provided ``AS IS'' and any express or implied            *
' *  warranties, including, but not limited to, the implied warranties of      *
' *  merchantability and fitness for a particular purpose, are disclaimed.     *
' *  In no event shall the authors be liable for any direct, indirect,         *
' *  incidental, special, exemplary, or consequential damages (including, but  *
' *  not limited to, procurement of substitute goods or services; loss of use, *
' *  data, or profits; or business interruption) however caused and on any     *
' *  theory of liability, whether in contract, strict liability, or tort       *
' *  ;(including negligence or otherwise) arising in any way out of the use of  *
' *  this software, even if advised of the possibility of such damage.         *
' *                                                                            *
' ******************************************************************************
'
'  CLASS: MD5
'
'  ;DESCRIPTION:
'     This is a class which encapsulates a set of MD5 Message Digest functions.
'     MD5 algorithm produces a 128 bit digital fingerprint (signature) from an
'     dataset of arbitrary length.  For details see RFC 1321 (summarized below).
'     This implementation is derived from the RSA Data Security, Inc. MD5 Message-Digest
'     algorithm reference implementation (originally written in C)
'
'  AUTHOR:
'     Robert M. Hubley 12/1999
'
'
'  NOTES:
'      Network Working Group                                    R. Rivest
'      Request for Comments: 1321     MIT Laboratory for Computer Science
'                                             and RSA Data Security, Inc.
'                                                              April 1992
'
'
'                           The MD5 Message-Digest Algorithm
'
'      Summary
'
'         This document describes the MD5 message-digest algorithm. The
'         algorithm takes as input a message of arbitrary length and produces
'         as output a 128-bit "fingerprint" or "message digest" of the input.
'         It is conjectured that it is computationally infeasible to produce
'         two messages having the same message digest, or to produce any
'         message having a given prespecified target message digest. The MD5
'         algorithm is intended for digital signature applications, where a
'         large file must be "compressed" in a secure manner before being
'         encrypted with a private (secret) key under a public-key cryptosystem
'         such as RSA.
'
'         The MD5 algorithm is designed to be quite fast on 32-bit machines. In
'         addition, the MD5 algorithm does not require any large substitution
'         tables; the algorithm can be coded quite compactly.
'
'         The MD5 algorithm is an extension of the MD4 message-digest algorithm
'         1,2]. MD5 is slightly slower than MD4, but is more "conservative" in
'         design. MD5 was designed because it was felt that MD4 was perhaps
'         being adopted for use more quickly than justified by the existing
'         critical review; because MD4 was designed to be exceptionally fast,
'         it is "at the edge" in terms of risking successful cryptanalytic
'         attack. MD5 backs off a bit, giving up a little in speed for a much
'         greater likelihood of ultimate security. It incorporates some
'         suggestions made by various reviewers, and contains additional
'         optimizations. The MD5 algorithm is being placed in the public domain
'         for review and possible adoption as a standard.
'
'         RFC Author:
'         Ronald L.Rivest
'         Massachusetts Institute of Technology
'         Laboratory for Computer Science
'         NE43 -324545    Technology Square
'         Cambridge, MA  02139-1986
'         Phone: (617) 253-5880
'         EMail:    Rivest@ theory.lcs.mit.edu
'
'
'
'  CHANGE HISTORY:
'
'     0.1.0  RMH    1999/12/29      Original version
'
'


'=
'= Class Constants
'=
Private Const OFFSET_4 = 4294967296#
Private Const MAXINT_4 = 2147483647

Private Const S11 = 7
Private Const S12 = 12
Private Const S13 = 17
Private Const S14 = 22
Private Const S21 = 5
Private Const S22 = 9
Private Const S23 = 14
Private Const S24 = 20
Private Const S31 = 4
Private Const S32 = 11
Private Const S33 = 16
Private Const S34 = 23
Private Const S41 = 6
Private Const S42 = 10
Private Const S43 = 15
Private Const S44 = 21


'=
'= Class Variables
'=
Private State(4) As Long
Private ByteCounter As Long
Private ByteBuffer(63) As Byte


'=
'= Class Properties
'=
Property Get RegisterA() As String
    RegisterA = State(1)
End Property

Property Get RegisterB() As String
    RegisterB = State(2)
End Property

Property Get RegisterC() As String
    RegisterC = State(3)
End Property

Property Get RegisterD() As String
    RegisterD = State(4)
End Property


'=
'= Class Functions
'=

'
' Function to quickly digest a file into a hex string
'
Public Function DigestFileToHexStr(FileName As String) As String
    Open FileName For Binary Access Read As #1
    MD5Init
    Do While Not EOF(1)
        Get #1, , ByteBuffer
        If Loc(1) < LOF(1) Then
            ByteCounter = ByteCounter + 64
            MD5Transform ByteBuffer
        End If
    Loop
    ByteCounter = ByteCounter + (LOF(1) Mod 64)
    Close #1
    MD5Final
    ;DigestFileToHexStr = GetValues
End Function

'
' Function to digest a text string and output the result as a string
' of hexadecimal characters.
'
Public Function DigestStrToHexStr(SourceString As String) As String
    MD5Init
    MD5Update Len(SourceString), StringToArray(SourceString)
    MD5Final
    ;DigestStrToHexStr = GetValues
End Function

'
' A utility function which converts a string into an array of
' bytes.
'
Private Function StringToArray(InString As String) As Byte()
    Dim I As Integer
    Dim bytBuffer() As Byte
    ReDim bytBuffer(Len(InString))
    For I = 0 To Len(InString) - 1
        bytBuffer(I) = Asc(Mid(InString, I + 1, 1))
    Next I
    StringToArray = bytBuffer
End Function

'
' Concatenate the four state vaules into one string
'
Public Function GetValues() As String
    GetValues = LongToString(State(1)) & LongToString(State(2)) & LongToString(State(3)) & LongToString(State(4))
End Function

'
' Convert a Long to a Hex string
'
Private Function LongToString(Num As Long) As String
        Dim a As Byte
        Dim b As Byte
        Dim c As Byte
        Dim d As Byte
        
        a = Num And &HFF&
        If a < 16 Then
            LongToString = "0" & Hex(a)
        Else
            LongToString = Hex(a)
        End If
               
        b = (Num And &HFF00&;) \ 256
        If b < 16 Then
            LongToString = LongToString & "0" & Hex(b)
        Else
            LongToString = LongToString & Hex(b)
        End If
        
        c = (Num And &HFF0000) \ 65536
        If c < 16 Then
            LongToString = LongToString & "0" & Hex(c)
        Else
            LongToString = LongToString & Hex(c)
        End If
       
        If Num < 0 Then
            d = ((Num And &H7F000000) \ 16777216) Or &H80&
        Else
            d = (Num And &HFF000000) \ 16777216
        End If
        
        If d < 16 Then
            LongToString = LongToString & "0" & Hex(d)
        Else
            LongToString = LongToString & Hex(d)
        End If
    
End Function

'
' Initialize the class
'   This must be called before a digest calculation is started
'
Public Sub MD5Init()
    ByteCounter = 0
    State(1) = UnsignedToLong(1732584193#)
    State(2) = UnsignedToLong(4023233417#)
    State(3) = UnsignedToLong(2562383102#)
    State(4) = UnsignedToLong(271733878#)
End Sub

'
' MD5 Final
'
Public Sub MD5Final()
    Dim dblBits As Double
    
    Dim padding(72) As Byte
    Dim lngBytesBuffered As Long
    
    padding(0) = &H80
    
    dblBits = ByteCounter * 8
    
    ' Pad out
    lngBytesBuffered = ByteCounter Mod 64
    If lngBytesBuffered <= 56 Then
        MD5Update 56 - lngBytesBuffered, padding
    Else
        MD5Update 120 - ByteCounter, padding
    End If
    
    
    padding(0) = UnsignedToLong(dblBits) And &HFF&
    padding(1) = UnsignedToLong(dblBits) \ 256 And &HFF&
    padding(2) = UnsignedToLong(dblBits) \ 65536 And &HFF&
    padding(3) = UnsignedToLong(dblBits) \ 16777216 And &HFF&
    padding(4) = 0
    padding(5) = 0
    padding(6) = 0
    padding(7) = 0
    
    MD5Update 8, padding
End Sub

'
' Break up input stream into 64 byte chunks
'
Public Sub MD5Update(InputLen As Long, InputBuffer() As Byte)
    Dim II As Integer
    Dim I As Integer
    Dim J As Integer
    Dim K As Integer
    Dim lngBufferedBytes As Long
    Dim lngBufferRemaining As Long
    Dim lngRem As Long
    
    lngBufferedBytes = ByteCounter Mod 64
    lngBufferRemaining = 64 - lngBufferedBytes
    ByteCounter = ByteCounter + InputLen
    ' Use up old buffer results first
    If InputLen >= lngBufferRemaining Then
        For II = 0 To lngBufferRemaining - 1
            ByteBuffer(lngBufferedBytes + II) = InputBuffer(II)
        Next II
        MD5Transform ByteBuffer
        
        lngRem = (InputLen) Mod 64
        ' The transfer is a multiple of 64 lets do some transformations
        For I = lngBufferRemaining To InputLen - II - lngRem Step 64
            For J = 0 To 63
                ByteBuffer(J) = InputBuffer(I + J)
            Next J
            MD5Transform ByteBuffer
        Next I
        lngBufferedBytes = 0
    Else
      I = 0
    End If
    
    ' Buffer any remaining input
    For K = 0 To InputLen - I - 1
        ByteBuffer(lngBufferedBytes + K) = InputBuffer(I + K)
    Next K
    
End Sub

'
' MD5 Transform
'
Private Sub MD5Transform(Buffer() As Byte)
    Dim x(16) As Long
    Dim a As Long
    Dim b As Long
    Dim c As Long
    Dim d As Long
    
    a = State(1)
    b = State(2)
    c = State(3)
    d = State(4)
    
    ;Decode 64, x, Buffer

    ' Round 1
    FF a, b, c, d, x(0), S11, -680876936
    FF d, a, b, c, x(1), S12, -389564586
    FF c, d, a, b, x(2), S13, 606105819
    FF b, c, d, a, x(3), S14, -1044525330
    FF a, b, c, d, x(4), S11, -176418897
    FF d, a, b, c, x(5), S12, 1200080426
    FF c, d, a, b, x(6), S13, -1473231341
    FF b, c, d, a, x(7), S14, -45705983
    FF a, b, c, d, x(8), S11, 1770035416
    FF d, a, b, c, x(9), S12, -1958414417
    FF c, d, a, b, x(10), S13, -42063
    FF b, c, d, a, x(11), S14, -1990404162
    FF a, b, c, d, x(12), S11, 1804603682
    FF d, a, b, c, x(13), S12, -40341101
    FF c, d, a, b, x(14), S13, -1502002290
    FF b, c, d, a, x(15), S14, 1236535329
    
    ' Round 2
    GG a, b, c, d, x(1), S21, -165796510
    GG d, a, b, c, x(6), S22, -1069501632
    GG c, d, a, b, x(11), S23, 643717713
    GG b, c, d, a, x(0), S24, -373897302
    GG a, b, c, d, x(5), S21, -701558691
    GG d, a, b, c, x(10), S22, 38016083
    GG c, d, a, b, x(15), S23, -660478335
    GG b, c, d, a, x(4), S24, -405537848
    GG a, b, c, d, x(9), S21, 568446438
    GG d, a, b, c, x(14), S22, -1019803690
    GG c, d, a, b, x(3), S23, -187363961
    GG b, c, d, a, x(8), S24, 1163531501
    GG a, b, c, d, x(13), S21, -1444681467
    GG d, a, b, c, x(2), S22, -51403784
    GG c, d, a, b, x(7), S23, 1735328473
    GG b, c, d, a, x(12), S24, -1926607734
    
    ' Round 3
    HH a, b, c, d, x(5), S31, -378558
    HH d, a, b, c, x(8), S32, -2022574463
    HH c, d, a, b, x(11), S33, 1839030562
    HH b, c, d, a, x(14), S34, -35309556
    HH a, b, c, d, x(1), S31, -1530992060
    HH d, a, b, c, x(4), S32, 1272893353
    HH c, d, a, b, x(7), S33, -155497632
    HH b, c, d, a, x(10), S34, -1094730640
    HH a, b, c, d, x(13), S31, 681279174
    HH d, a, b, c, x(0), S32, -358537222
    HH c, d, a, b, x(3), S33, -722521979
    HH b, c, d, a, x(6), S34, 76029189
    HH a, b, c, d, x(9), S31, -640364487
    HH d, a, b, c, x(12), S32, -421815835
    HH c, d, a, b, x(15), S33, 530742520
    HH b, c, d, a, x(2), S34, -995338651
    
    ' Round 4
    II a, b, c, d, x(0), S41, -198630844
    II d, a, b, c, x(7), S42, 1126891415
    II c, d, a, b, x(14), S43, -1416354905
    II b, c, d, a, x(5), S44, -57434055
    II a, b, c, d, x(12), S41, 1700485571
    II d, a, b, c, x(3), S42, -1894986606
    II c, d, a, b, x(10), S43, -1051523
    II b, c, d, a, x(1), S44, -2054922799
    II a, b, c, d, x(8), S41, 1873313359
    II d, a, b, c, x(15), S42, -30611744
    II c, d, a, b, x(6), S43, -1560198380
    II b, c, d, a, x(13), S44, 1309151649
    II a, b, c, d, x(4), S41, -145523070
    II d, a, b, c, x(11), S42, -1120210379
    II c, d, a, b, x(2), S43, 718787259
    II b, c, d, a, x(9), S44, -343485551
    
    
    State(1) = LongOverflowAdd(State(1), a)
    State(2) = LongOverflowAdd(State(2), b)
    State(3) = LongOverflowAdd(State(3), c)
    State(4) = LongOverflowAdd(State(4), d)

'  /* Zeroize sensitive information.
'*/
'  MD5_memset ((POINTER)x, 0, sizeof (x));
    
End Sub

Private Sub Decode(Length As Integer, OutputBuffer() As Long, InputBuffer() As Byte)
    Dim intDblIndex As Integer
    Dim intByteIndex As Integer
    Dim dblSum As Double
    
    intDblIndex = 0
    For intByteIndex = 0 To Length - 1 Step 4
        dblSum = InputBuffer(intByteIndex) + _
                                    InputBuffer(intByteIndex + 1) * 256# + _
                                    InputBuffer(intByteIndex + 2) * 65536# + _
                                    InputBuffer(intByteIndex + 3) * 16777216#
        OutputBuffer(intDblIndex) = UnsignedToLong(dblSum)
        intDblIndex = intDblIndex + 1
    Next intByteIndex
End Sub

'
' FF, GG, HH, and II transformations for rounds 1, 2, 3, and 4.
' Rotation is separate from addition to prevent recomputation.
'
Private Function FF(a As Long, _
                    b As Long, _
                    c As Long, _
                    d As Long, _
                    x As Long, _
                    s As Long, _
                    ac As Long) As Long
    a = LongOverflowAdd4(a, (b And c) Or (Not (b) And d), x, ac)
    a = LongLeftRotate(a, s)
    a = LongOverflowAdd(a, b)
End Function

Private Function GG(a As Long, _
                    b As Long, _
                    c As Long, _
                    d As Long, _
                    x As Long, _
                    s As Long, _
                    ac As Long) As Long
    a = LongOverflowAdd4(a, (b And d) Or (c And Not (d)), x, ac)
    a = LongLeftRotate(a, s)
    a = LongOverflowAdd(a, b)
End Function

Private Function HH(a As Long, _
                    b As Long, _
                    c As Long, _
                    d As Long, _
                    x As Long, _
                    s As Long, _
                    ac As Long) As Long
    a = LongOverflowAdd4(a, b Xor c Xor d, x, ac)
    a = LongLeftRotate(a, s)
    a = LongOverflowAdd(a, b)
End Function

Private Function II(a As Long, _
                    b As Long, _
                    c As Long, _
                    d As Long, _
                    x As Long, _
                    s As Long, _
                    ac As Long) As Long
    a = LongOverflowAdd4(a, c Xor (b Or Not (d)), x, ac)
    a = LongLeftRotate(a, s)
    a = LongOverflowAdd(a, b)
End Function

'
' Rotate a long to the right
'
Function LongLeftRotate(value As Long, bits As Long) As Long
    Dim lngSign As Long
    Dim lngI As Long
    bits = bits Mod 32
    If bits = 0 Then LongLeftRotate = value: Exit Function
    For lngI = 1 To bits
        lngSign = value And &HC0000000
        value = (value And &H3FFFFFFF) * 2
        value = value Or ((lngSign < 0) And 1) Or (CBool(lngSign And _
                &H40000000) And &H80000000)
    Next
    LongLeftRotate = value
End Function

'
' Function to add two unsigned numbers together as in C.
' Overflows are ignored!
'
Private Function LongOverflowAdd(Val1 As Long, Val2 As Long) As Long
    Dim lngHighWord As Long
    Dim lngLowWord As Long
    Dim lngOverflow As Long

    lngLowWord = (Val1 And &HFFFF&;) + (Val2 And &HFFFF&;)
    lngOverflow = lngLowWord \ 65536
    lngHighWord = (((Val1 And &HFFFF0000) \ 65536) + ((Val2 And &HFFFF0000) \ 65536) + lngOverflow) And &HFFFF&
    LongOverflowAdd = UnsignedToLong((lngHighWord * 65536#) + (lngLowWord And &HFFFF&;))
End Function

'
' Function to add two unsigned numbers together as in C.
' Overflows are ignored!
'
Private Function LongOverflowAdd4(Val1 As Long, Val2 As Long, val3 As Long, val4 As Long) As Long
    Dim lngHighWord As Long
    Dim lngLowWord As Long
    Dim lngOverflow As Long

    lngLowWord = (Val1 And &HFFFF&;) + (Val2 And &HFFFF&;) + (val3 And &HFFFF&;) + (val4 And &HFFFF&;)
    lngOverflow = lngLowWord \ 65536
    lngHighWord = (((Val1 And &HFFFF0000) \ 65536) + _
                   ;((Val2 And &HFFFF0000) \ 65536) + _
                   ;((val3 And &HFFFF0000) \ 65536) + _
                   ;((val4 And &HFFFF0000) \ 65536) + _
                   lngOverflow) And &HFFFF&
    LongOverflowAdd4 = UnsignedToLong((lngHighWord * 65536#) + (lngLowWord And &HFFFF&;))
End Function

'
' Convert an unsigned double into a long
'
Private Function UnsignedToLong(value As Double) As Long
        If value < 0 Or value >= OFFSET_4 Then Error 6 ' Overflow
        If value <= MAXINT_4 Then
          UnsignedToLong = value
        Else
          UnsignedToLong = value - OFFSET_4
        End If
      End Function

'
' Convert a long to an unsigned Double
'
Private Function LongToUnsigned(value As Long) As Double
        If value < 0 Then
          LongToUnsigned = value + OFFSET_4
        Else
          LongToUnsigned = value
        End If
End Function



форма:


Option Explicit
'/******************************************************************************
' *  Copyright (C) 2000 by Robert Hubley.                                      *
' *  All rights reserved.                                                      *
' *                                                                            *
' *  This software is provided ``AS IS'' and any express or implied            *
' *  warranties, including, but not limited to, the implied warranties of      *
' *  merchantability and fitness for a particular purpose, are disclaimed.     *
' *  In no event shall the authors be liable for any direct, indirect,         *
' *  incidental, special, exemplary, or consequential damages (including, but  *
' *  not limited to, procurement of substitute goods or services; loss of use, *
' *  data, or profits; or business interruption) however caused and on any     *
' *  theory of liability, whether in contract, strict liability, or tort       *
' *  ;(including negligence or otherwise) arising in any way out of the use of  *
' *  this software, even if advised of the possibility of such damage.         *
' *                                                                            *
' ******************************************************************************
'
'  Form: TestSuite
'
'  ;DESCRIPTION:
'   A short demonstration form which calls the MD5.DLL library using a
'   standard test suite of values.  The results are displayed next to the
'   expected return set for comparison.
'
'  AUTHOR:
'     Robert M. Hubley 12/1999
'
'
'  NOTES:
'
'
'  CHANGE HISTORY:
'
'     1.0.0  RMH    2000/1/5      Original version
'
'

'= Global Variables
Dim md5Test As MD5


Private Sub btnRunTest_Click()
    lblResults(0).Caption = LCase(md5Test.DigestStrToHexStr("";))
    lblResults(1).Caption = LCase(md5Test.DigestStrToHexStr("a";))
    lblResults(2).Caption = LCase(md5Test.DigestStrToHexStr("abc";))
    lblResults(3).Caption = LCase(md5Test.DigestStrToHexStr("message digest";))
    lblResults(4).Caption = LCase(md5Test.DigestStrToHexStr("abcdefghijklmnopqrstuvwxyz";))
    lblResults(5).Caption = LCase(md5Test.DigestStrToHexStr("ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789";))
    lblResults(6).Caption = LCase(md5Test.DigestStrToHexStr("12345678901234567890123456789012345678901234567890123456789012345678901234567890";))
End Sub


Private Sub Form_Load()
    ' Instantiate our class
    Set md5Test = New MD5
End Sub

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Номер ответа: 4
Автор ответа:
 GSerg



Вопросов: 0
Ответов: 1876


 Профиль | | #4 Добавлено: 23.07.05 15:48
А что же это по-вашему?

Это, по-нашему, алгоритм хэширования...

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Номер ответа: 5
Автор ответа:
 GlooM



ICQ: 348453688 

Вопросов: 88
Ответов: 356
 Web-сайт: newlc.info
 Профиль | | #5
Добавлено: 23.07.05 16:32
MD5 - Умер!!!!

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Номер ответа: 6
Автор ответа:
 Artyom



Разработчик

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 Профиль | | #6 Добавлено: 23.07.05 16:32
Спроси у Sharp'а.
Он в свое время тоже пытался "расшифровать" MD5, но вовремя понял, что лучше этого не делать :)

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 ViktorZ



ICQ: 271202919 

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 Профиль | | #7 Добавлено: 23.07.05 16:40
Странно, а чем расшифровываются всем известные хеши? MD5 Crack- прога которая расшифровывает MD5. Да таких программ куча.

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Автор ответа:
 Voland



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 Профиль | | #8 Добавлено: 23.07.05 16:43
MD5 невозможно расщифровать.
Можно перебором найти данные, хэш которых будет совпадать с хешем зашифрованных данных, но это не есть расшифровка, да и займет заведомо много времени.

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Номер ответа: 9
Автор ответа:
 MixeR



Вопросов: 12
Ответов: 25
 Профиль | | #9 Добавлено: 23.07.05 19:00
GSergхэширования...хорошо пусть будет хеширования:)

нашёл в инете готовый VBScript, похожий на пример который привёл HACKER.
И так кидаем его в директорию где у нас лежит страничка и поехали
в файле
<script Language="VBscript" src=md5.vbs>
   MsgBox MD5("mixer";)
  </script>

не работает:( сообщение не выводит!

А если делаем так, то получаем хешированное значение.
<script Language="VBscript">
тут полностью содержимео файла
md5.vbs
MsgBox MD5("mixer";)
</script>

как можно заставить работать первый метод?

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Автор ответа:
 HACKER


 

Разработчик Offline Client

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 Профиль | | #10 Добавлено: 23.07.05 19:18
так тебе на VBS надо что-ли?

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 Morpheus



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 Web-сайт: xury.zx6.ru
 Профиль | | #11
Добавлено: 23.07.05 19:59
Я щас минуты две катился от смеха... вот почему:
Написал в блокноте (!) вот это код, похоже даже нерабочий:

<script Language="VBscript">
for i=1 to 10
document.write("FGH";)
next i
</script>

Ну сообщения то я ожидал, но уж точно не от Касперского... выдаёт: Обнаружен вирус Trojan.VBS.lFrame

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 Artyom



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 Профиль | | #12 Добавлено: 23.07.05 21:24
А почему бы не воспользовать готовыми решениями, вычисляющими хэш MD5, а не
городить свой забор на коленке?

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Номер ответа: 13
Автор ответа:
 MixeR



Вопросов: 12
Ответов: 25
 Профиль | | #13 Добавлено: 23.07.05 21:30
дак никто и не городит:)
вот готовый md5.vbs

Private Const BITS_TO_A_BYTE = 8
Private Const BYTES_TO_A_WORD = 4
Private Const BITS_TO_A_WORD = 32

Private m_lOnBits(30)
Private m_l2Power(30)
 
    m_lOnBits(0) = CLng(1)
    m_lOnBits(1) = CLng(3)
    m_lOnBits(2) = CLng(7)
    m_lOnBits(3) = CLng(15)
    m_lOnBits(4) = CLng(31)
    m_lOnBits(5) = CLng(63)
    m_lOnBits(6) = CLng(127)
    m_lOnBits(7) = CLng(255)
    m_lOnBits(8) = CLng(511)
    m_lOnBits(9) = CLng(1023)
    m_lOnBits(10) = CLng(2047)
    m_lOnBits(11) = CLng(4095)
    m_lOnBits(12) = CLng(8191)
    m_lOnBits(13) = CLng(16383)
    m_lOnBits(14) = CLng(32767)
    m_lOnBits(15) = CLng(65535)
    m_lOnBits(16) = CLng(131071)
    m_lOnBits(17) = CLng(262143)
    m_lOnBits(18) = CLng(524287)
    m_lOnBits(19) = CLng(1048575)
    m_lOnBits(20) = CLng(2097151)
    m_lOnBits(21) = CLng(4194303)
    m_lOnBits(22) = CLng(8388607)
    m_lOnBits(23) = CLng(16777215)
    m_lOnBits(24) = CLng(33554431)
    m_lOnBits(25) = CLng(67108863)
    m_lOnBits(26) = CLng(134217727)
    m_lOnBits(27) = CLng(268435455)
    m_lOnBits(28) = CLng(536870911)
    m_lOnBits(29) = CLng(1073741823)
    m_lOnBits(30) = CLng(2147483647)
    
    m_l2Power(0) = CLng(1)
    m_l2Power(1) = CLng(2)
    m_l2Power(2) = CLng(4)
    m_l2Power(3) = CLng(8)
    m_l2Power(4) = CLng(16)
    m_l2Power(5) = CLng(32)
    m_l2Power(6) = CLng(64)
    m_l2Power(7) = CLng(128)
    m_l2Power(8) = CLng(256)
    m_l2Power(9) = CLng(512)
    m_l2Power(10) = CLng(1024)
    m_l2Power(11) = CLng(2048)
    m_l2Power(12) = CLng(4096)
    m_l2Power(13) = CLng(8192)
    m_l2Power(14) = CLng(16384)
    m_l2Power(15) = CLng(32768)
    m_l2Power(16) = CLng(65536)
    m_l2Power(17) = CLng(131072)
    m_l2Power(18) = CLng(262144)
    m_l2Power(19) = CLng(524288)
    m_l2Power(20) = CLng(1048576)
    m_l2Power(21) = CLng(2097152)
    m_l2Power(22) = CLng(4194304)
    m_l2Power(23) = CLng(8388608)
    m_l2Power(24) = CLng(16777216)
    m_l2Power(25) = CLng(33554432)
    m_l2Power(26) = CLng(67108864)
    m_l2Power(27) = CLng(134217728)
    m_l2Power(28) = CLng(268435456)
    m_l2Power(29) = CLng(536870912)
    m_l2Power(30) = CLng(1073741824)

Private Function LShift(lValue, iShiftBits)
    If iShiftBits = 0 Then
        LShift = lValue
        Exit Function
    ElseIf iShiftBits = 31 Then
        If lValue And 1 Then
            LShift = &H80000000
        Else
            LShift = 0
        End If
        Exit Function
    ElseIf iShiftBits < 0 Or iShiftBits > 31 Then
        Err.Raise 6
    End If

    If (lValue And m_l2Power(31 - iShiftBits)) Then
        LShift = ((lValue And m_lOnBits(31 - (iShiftBits + 1))) * m_l2Power(iShiftBits)) Or &H80000000
    Else
        LShift = ((lValue And m_lOnBits(31 - iShiftBits)) * m_l2Power(iShiftBits))
    End If
End Function

Private Function RShift(lValue, iShiftBits)
    If iShiftBits = 0 Then
        RShift = lValue
        Exit Function
    ElseIf iShiftBits = 31 Then
        If lValue And &H80000000 Then
            RShift = 1
        Else
            RShift = 0
        End If
        Exit Function
    ElseIf iShiftBits < 0 Or iShiftBits > 31 Then
        Err.Raise 6
    End If
    
    RShift = (lValue And &H7FFFFFFE) \ m_l2Power(iShiftBits)

    If (lValue And &H80000000) Then
        RShift = (RShift Or (&H40000000 \ m_l2Power(iShiftBits - 1)))
    End If
End Function

Private Function RotateLeft(lValue, iShiftBits)
    RotateLeft = LShift(lValue, iShiftBits) Or RShift(lValue, (32 - iShiftBits))
End Function

Private Function AddUnsigned(lX, lY)
    Dim lX4
    Dim lY4
    Dim lX8
    Dim lY8
    Dim lResult
 
    lX8 = lX And &H80000000
    lY8 = lY And &H80000000
    lX4 = lX And &H40000000
    lY4 = lY And &H40000000
 
    lResult = (lX And &H3FFFFFFF) + (lY And &H3FFFFFFF)
 
    If lX4 And lY4 Then
        lResult = lResult Xor &H80000000 Xor lX8 Xor lY8
    ElseIf lX4 Or lY4 Then
        If lResult And &H40000000 Then
            lResult = lResult Xor &HC0000000 Xor lX8 Xor lY8
        Else
            lResult = lResult Xor &H40000000 Xor lX8 Xor lY8
        End If
    Else
        lResult = lResult Xor lX8 Xor lY8
    End If
 
    AddUnsigned = lResult
End Function

Private Function F(x, y, z)
    F = (x And y) Or ((Not x) And z)
End Function

Private Function G(x, y, z)
    G = (x And z) Or (y And (Not z))
End Function

Private Function H(x, y, z)
    H = (x Xor y Xor z)
End Function

Private Function I(x, y, z)
    I = (y Xor (x Or (Not z)))
End Function

Private Sub FF(a, b, c, d, x, s, ac)
    a = AddUnsigned(a, AddUnsigned(AddUnsigned(F(b, c, d), x), ac))
    a = RotateLeft(a, s)
    a = AddUnsigned(a, b)
End Sub

Private Sub GG(a, b, c, d, x, s, ac)
    a = AddUnsigned(a, AddUnsigned(AddUnsigned(G(b, c, d), x), ac))
    a = RotateLeft(a, s)
    a = AddUnsigned(a, b)
End Sub

Private Sub HH(a, b, c, d, x, s, ac)
    a = AddUnsigned(a, AddUnsigned(AddUnsigned(H(b, c, d), x), ac))
    a = RotateLeft(a, s)
    a = AddUnsigned(a, b)
End Sub

Private Sub II(a, b, c, d, x, s, ac)
    a = AddUnsigned(a, AddUnsigned(AddUnsigned(I(b, c, d), x), ac))
    a = RotateLeft(a, s)
    a = AddUnsigned(a, b)
End Sub

Private Function ConvertToWordArray(sMessage)
    Dim lMessageLength
    Dim lNumberOfWords
    Dim lWordArray()
    Dim lBytePosition
    Dim lByteCount
    Dim lWordCount
    
    Const MODULUS_BITS = 512
    Const CONGRUENT_BITS = 448
    
    lMessageLength = Len(sMessage)
    
    lNumberOfWords = (((lMessageLength + ((MODULUS_BITS - CONGRUENT_BITS) \ BITS_TO_A_BYTE)) \ (MODULUS_BITS \ BITS_TO_A_BYTE)) + 1) * (MODULUS_BITS \ BITS_TO_A_WORD)
    ReDim lWordArray(lNumberOfWords - 1)
    
    lBytePosition = 0
    lByteCount = 0
    Do Until lByteCount >= lMessageLength
        lWordCount = lByteCount \ BYTES_TO_A_WORD
        lBytePosition = (lByteCount Mod BYTES_TO_A_WORD) * BITS_TO_A_BYTE
        lWordArray(lWordCount) = lWordArray(lWordCount) Or LShift(Asc(Mid(sMessage, lByteCount + 1, 1)), lBytePosition)
        lByteCount = lByteCount + 1
    Loop

    lWordCount = lByteCount \ BYTES_TO_A_WORD
    lBytePosition = (lByteCount Mod BYTES_TO_A_WORD) * BITS_TO_A_BYTE

    lWordArray(lWordCount) = lWordArray(lWordCount) Or LShift(&H80, lBytePosition)

    lWordArray(lNumberOfWords - 2) = LShift(lMessageLength, 3)
    lWordArray(lNumberOfWords - 1) = RShift(lMessageLength, 29)
    
    ConvertToWordArray = lWordArray
End Function

Private Function WordToHex(lValue)
    Dim lByte
    Dim lCount
    
    For lCount = 0 To 3
        lByte = RShift(lValue, lCount * BITS_TO_A_BYTE) And m_lOnBits(BITS_TO_A_BYTE - 1)
        WordToHex = WordToHex & Right("0" & Hex(lByte), 2)
    Next
End Function

Public Function MD5(sMessage)
    Dim x
    Dim k
    Dim AA
    Dim BB
    Dim CC
    Dim DD
    Dim a
    Dim b
    Dim c
    Dim d
    
    Const S11 = 7
    Const S12 = 12
    Const S13 = 17
    Const S14 = 22
    Const S21 = 5
    Const S22 = 9
    Const S23 = 14
    Const S24 = 20
    Const S31 = 4
    Const S32 = 11
    Const S33 = 16
    Const S34 = 23
    Const S41 = 6
    Const S42 = 10
    Const S43 = 15
    Const S44 = 21

    x = ConvertToWordArray(sMessage)
    
    a = &H67452301
    b = &HEFCDAB89
    c = &H98BADCFE
    d = &H10325476

    For k = 0 To UBound(x) Step 16
        AA = a
        BB = b
        CC = c
        ;DD = d
    
        FF a, b, c, d, x(k + 0), S11, &HD76AA478
        FF d, a, b, c, x(k + 1), S12, &HE8C7B756
        FF c, d, a, b, x(k + 2), S13, &H242070DB
        FF b, c, d, a, x(k + 3), S14, &HC1BDCEEE
        FF a, b, c, d, x(k + 4), S11, &HF57C0FAF
        FF d, a, b, c, x(k + 5), S12, &H4787C62A
        FF c, d, a, b, x(k + 6), S13, &HA8304613
        FF b, c, d, a, x(k + 7), S14, &HFD469501
        FF a, b, c, d, x(k + 8), S11, &H698098D8
        FF d, a, b, c, x(k + 9), S12, &H8B44F7AF
        FF c, d, a, b, x(k + 10), S13, &HFFFF5BB1
        FF b, c, d, a, x(k + 11), S14, &H895CD7BE
        FF a, b, c, d, x(k + 12), S11, &H6B901122
        FF d, a, b, c, x(k + 13), S12, &HFD987193
        FF c, d, a, b, x(k + 14), S13, &HA679438E
        FF b, c, d, a, x(k + 15), S14, &H49B40821
    
        GG a, b, c, d, x(k + 1), S21, &HF61E2562
        GG d, a, b, c, x(k + 6), S22, &HC040B340
        GG c, d, a, b, x(k + 11), S23, &H265E5A51
        GG b, c, d, a, x(k + 0), S24, &HE9B6C7AA
        GG a, b, c, d, x(k + 5), S21, &HD62F105D
        GG d, a, b, c, x(k + 10), S22, &H2441453
        GG c, d, a, b, x(k + 15), S23, &HD8A1E681
        GG b, c, d, a, x(k + 4), S24, &HE7D3FBC8
        GG a, b, c, d, x(k + 9), S21, &H21E1CDE6
        GG d, a, b, c, x(k + 14), S22, &HC33707D6
        GG c, d, a, b, x(k + 3), S23, &HF4D50D87
        GG b, c, d, a, x(k + 8), S24, &H455A14ED
        GG a, b, c, d, x(k + 13), S21, &HA9E3E905
        GG d, a, b, c, x(k + 2), S22, &HFCEFA3F8
        GG c, d, a, b, x(k + 7), S23, &H676F02D9
        GG b, c, d, a, x(k + 12), S24, &H8D2A4C8A
            
        HH a, b, c, d, x(k + 5), S31, &HFFFA3942
        HH d, a, b, c, x(k + 8), S32, &H8771F681
        HH c, d, a, b, x(k + 11), S33, &H6D9D6122
        HH b, c, d, a, x(k + 14), S34, &HFDE5380C
        HH a, b, c, d, x(k + 1), S31, &HA4BEEA44
        HH d, a, b, c, x(k + 4), S32, &H4BDECFA9
        HH c, d, a, b, x(k + 7), S33, &HF6BB4B60
        HH b, c, d, a, x(k + 10), S34, &HBEBFBC70
        HH a, b, c, d, x(k + 13), S31, &H289B7EC6
        HH d, a, b, c, x(k + 0), S32, &HEAA127FA
        HH c, d, a, b, x(k + 3), S33, &HD4EF3085
        HH b, c, d, a, x(k + 6), S34, &H4881D05
        HH a, b, c, d, x(k + 9), S31, &HD9D4D039
        HH d, a, b, c, x(k + 12), S32, &HE6DB99E5
        HH c, d, a, b, x(k + 15), S33, &H1FA27CF8
        HH b, c, d, a, x(k + 2), S34, &HC4AC5665
    
        II a, b, c, d, x(k + 0), S41, &HF4292244
        II d, a, b, c, x(k + 7), S42, &H432AFF97
        II c, d, a, b, x(k + 14), S43, &HAB9423A7
        II b, c, d, a, x(k + 5), S44, &HFC93A039
        II a, b, c, d, x(k + 12), S41, &H655B59C3
        II d, a, b, c, x(k + 3), S42, &H8F0CCC92
        II c, d, a, b, x(k + 10), S43, &HFFEFF47D
        II b, c, d, a, x(k + 1), S44, &H85845DD1
        II a, b, c, d, x(k + 8), S41, &H6FA87E4F
        II d, a, b, c, x(k + 15), S42, &HFE2CE6E0
        II c, d, a, b, x(k + 6), S43, &HA3014314
        II b, c, d, a, x(k + 13), S44, &H4E0811A1
        II a, b, c, d, x(k + 4), S41, &HF7537E82
        II d, a, b, c, x(k + 11), S42, &HBD3AF235
        II c, d, a, b, x(k + 2), S43, &H2AD7D2BB
        II b, c, d, a, x(k + 9), S44, &HEB86D391
    
        a = AddUnsigned(a, AA)
        b = AddUnsigned(b, BB)
        c = AddUnsigned(c, CC)
        d = AddUnsigned(d, DD)
    Next
    
    MD5 = UCase(WordToHex(a) & WordToHex(b) & WordToHex(c) & WordToHex(d))
End Function


И вот так вот пробую
1метод

<script Language="VBscript" src=md5.vbs>
   MsgBox MD5("mixer";)
  </script>


2метод
<script Language="VBscript">
тут полностью содержимео файла
md5.vbs
MsgBox MD5("mixer";)
</script>

почему второй метод работает, а первый молчит:(

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Номер ответа: 14
Автор ответа:
 Artyom



Разработчик

Вопросов: 130
Ответов: 6602
 Профиль | | #14 Добавлено: 23.07.05 22:07
Я имею в виду CryptoAPI.

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Номер ответа: 15
Автор ответа:
 HACKER


 

Разработчик Offline Client

Вопросов: 236
Ответов: 8362
 Профиль | | #15 Добавлено: 23.07.05 23:34
помойму VBS в HTML не разрешает использовать API, а то бы страшные вещи делать можно было ;) ...

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